The Winning Roulette System
Posted: Friday, June 09, 2006
by How To Bet
http://www.webgoldminer.com/
Is it possible to earn money from online gambling? Are there any 100% sure winning roulette systems? Are there actually people who make a living from gambling? The three questions have a same answer – yes.
1. Choosing a better online casino.
Every online casino has a specific payout. An online casino payout is a number that is calculated from monthly statistics usually by a third party auditing firm. The payout value describes how much of the casino's monthly turnaround returns to players and how much is kept by casino. It is calculated from actual casino software logs for all games played in the casino during the past month. As all casino games are precisely balanced from statistical viewpoint the payout dynamics comes from elsewhere and casinos with highest payout ratios are more attractive to the players because players have better chance to win. The payouts at the different online casinos vary from 95% to about 99%. For example: an online casino with reported 98.5% payout implies that out of (hypothetical) $1,000,000 that players wagered last month $985,000 was won back or otherwise taken by the players, leaving the casino with only $15,000. So, one of the things that you always must look for is the casino's payout. The bigger the better. The fair too, because there is always a chance to be deceived from a casino with no declared payout.
2. Introduction to the Roulette game.
The Roulette is the most fair casino game (from the games that you play against the casino of course). Why? Because of the bet payoffs, which are the same for all roulettes in every casino and the efficient value – (chance to win the betting) x (payoff coefficient). This efficient value in one slot game for example is much smaller (vary from 30% to 90% according to the slot machine type) than the roulettes' (which vary from 92,1% to 94,7%).
As you know the roulette has 38 numbers – 0, 00, 1, 2, 3 … 35, 36. The chance to win a betting is formed by the ratio – (count of the numbers you have chosen as your bet) / 38. For example: You make a four-number bet (28, 29, 31, 32). Your chance to win this betting is: 4 / 38 = 0,105 or 10,5%.
Payoff 2 to 1 means a payoff coefficient 3. For example: You make a column bet and you put 100$ in chips on one of the three columns. If you win, you take your 100$ plus 200$ (because the payoff is 2 to 1). This makes 300$. The payoff coefficient forms from the ratio – money after possible win / staked money or in this case: 300 / 100 = 3. You can receive this coefficient in one other way too – simply replace in the payoff phrase "to" with "+" (2 to 1 = 2 + 1 = 3).
And finally – what actually means "efficient value"? This is the probability to win from the casino. For example: You come in the casino with 5000$. You play the whole day and in the end your money are more, if the efficient value of the game you played is more than 100%. The following formula describes this – (your start money) x [(efficient value of the game you play) to the (played hours) power] = (your end money).
Here are all the roulette bets possibilities, chances to win, payoff coefficients and efficient values:
|
N |
Bet type |
Chance to win |
Payoff coeff. |
Efficient value |
|
1 |
Straight bet |
2,63 % |
36 |
94,7 % |
|
2 |
Split bet |
5,26 % |
18 |
94,7 % |
|
3 |
Street bet |
7,89 % |
12 |
94,7 % |
|
4 |
Corner bet |
10,52 % |
9 |
94,7 % |
|
5 |
Five-Number bet |
13,15 % |
7 |
92,1 % |
|
6 |
Six-Line bet |
15,79 % |
6 |
94,7 % |
|
7 |
Dozen, Column bet |
31,58 % |
3 |
94,7 % |
|
8 |
Red, Black, Even, Odd, Low, High bet |
47,37 % |
2 |
94,7 % |
May be you've noticed that the efficient values of all betting types are under 100%. Does this means that you will always lose from the most fair casino game? Yes. Every regular player that plays at the roulette for long time will have less money at the end. What if I make a big straight bet and I win, I'll get ahead with a lot of money, won't I? Yes, you will, but you can't win every day in such way. After some period of time, in which you will lose little by little, you will reach your start money again. So, you can't make a living in such way. The casino earn from the regular players. But not from all players. And here comes the betting strategies, which help you win the "unbeatable roulette". But first…
3. Choosing a betting type.
As you can see from the bets descriptions above, only the five-number bet efficien value is different from the others (with 2,6% smaller). So one of the eight bet possibilities fades out from the choice of "wanna be a winner" player. But the other seven bet types have the same efficient value. So, the next thing, in which we compare these seven types is the chance to win the betting. The bigger chance means that you'll need less start money to fulfil your strategy. And the 8) betting type has the biggest chance to win the betting. But there are six possible bets from this type. You can place money on red, black, even, odd, low or high. The "winning order" comes here…
4. Introduction to the strategy.
Do you know, what is a geometric progression? Here is one example for those of you who don’t know: The numbers 1, 2, 4, 8, 16, 32 are given. Can you guess which is the next number? It's 64. The relation between the numbers is that every number from the sequence is twice bigger from the previous. A sequence from numbers with any relation valid for all numbers from the sequence is called progression. The betting strategy rely on a simple geometric progression. Check the following table:
|
Bet Number |
Stake ( $ ) |
Gain ( $ ) |
|
1 |
1 |
+ 1 |
|
2 |
2 |
+ 1 |
|
3 |
4 |
+ 1 |
|
4 |
8 |
+ 1 |
|
5 |
16 |
+ 1 |
|
6 |
32 |
+ 1 |
|
7 |
64 |
+ 1 |
|
8 |
128 |
+ 1 |
|
9 |
256 |
+ 1 |
This table describes the following thing:
|
So, now you ask yourself – what is the chance to have 9 times no red number?
And here comes the probability theory in help. The chance the ball to stop on a black number, 0 or 00 is: 100% - (your chance to win the betting on "Red") = 100% - 47,37% = 52,63%. The first time you place a bet on "Red" the chance to lose is 52,63%. But the second time this chance changes. Why? The "Independent Events" is one chapter of the probability theory. Two events are said to be independent, if the result of the second event is not affected by the result of the first event. If A and B are independent events, the probability of both events occurring is the product of their individual probabilities. If you can't understand this, here you'll find one very nice explanation - http://regentsprep.org/Regents/Math/mutual/Lindep.htm. The following table is based upon the probability theory and shows how the chance to lose changes with every next bet you place on "Red":
|
Bet Number |
Chance to lose |
|
1 |
52,63 % |
|
2 |
27,69 % |
|
3 |
14,57 % |
|
4 |
7,67 % |
|
5 |
4,03 % |
|
6 |
2,12 % |
|
7 |
1,11 % |
|
8 |
0,58 % |
|
9 |
0,30 % |
|
10 |
0,16 % |
|
11 |
0,08 % |
You can find this system here - WEBGOLDMINER WINNING ROULETTE SYSTEM
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Top-level comments on this article: (9 total)#1 Roulette System!
What a joke. Anyone with half a brain knows this wont work. The roulette table has no memory! the ball may have landed on black for the past 25 goes but the odds on another black will still be the same as when you started!
Gary you are in big mistake. See this example: A drawer contains 3 red, 4 green, and 5 blue paperclips. One paperclip is taken from the drawer and then replaced. Another paperclip is taken from the drawer. What is the probability that the first paperclip is red and the second paperclip is blue? P(red then blue) = P(red) x P(blue) = 3/12 * 5/12 = 15/144 = 5/48. With the roulette table is exatly the same thing: P(black than black) = P(black) x P(black) = 18/38 * 18/38 = 81/361.
The math is wrong! When you lose after nine times (which happens 3 in every 1,000) you lose $511, this is correct as this is the sum of the nine bets.
However, when you lose after 11 times, you do not lose $511 x 3. you lose the sum of 11 bets three times! this is $511 (after nine bets) + $312 (the money you lose on the tenth bet) +$624 (the money you lose on the twelfth bet) = $1447 x 3. This will give you a loss as you only win $1997.
Sorry for bursting your bubble, but this is correct, it is a common mistake.The idea is that you can make free spins (or just pass some spins while other bet), so that 2 spins are already done and then you make 9 bets in a row + these 2 = 11.
What a joke this system is. I have tried this system before and it is a loser. Every time i go to the casino you always see a run of 10 of the same colour or more. I once seen 26 reds in a row with the 0 in between. Unless you take about £100,000 with you and the tables have unlimitted bets on then yes you may win most of the time and have enough money to keep doubling up. But for the average person who takes upto £500 then system doesnt work. Been there, done it got the t shirt.
Very good system!
you must be a pure idiot.......do not fill internet space with this crap...ply real money and you see your system is good only to shove it up in your asssssssssss
you must be a pure idiot.......do not fill internet space with this crap...ply real money and you see your system is good only to shove it up in your asssssssssss
Yeah right, online casino roulette is purely a game of chance.
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